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Introduce _split_pattern to parse an "x:y:z" pattern
This function takes a string like 'foo:bar[1:2]:baz[x:y]-quux' and returns a list of patterns ['foo', 'bar[1:2]', 'baz[x:y]-quux'], i.e. splits the string on colons that are not part of a range specification.
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1 changed files with 20 additions and 3 deletions
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@ -155,6 +155,23 @@ class Inventory(object):
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results.append(item)
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return results
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def _split_pattern(self, pattern):
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"""
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takes e.g. "webservers[0:5]:dbservers:others"
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and returns ["webservers[0:5]", "dbservers", "others"]
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"""
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term = re.compile(
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r'''(?: # We want to match something comprising:
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[^:\[\]] # (anything other than ':', '[', or ']'
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| # ...or...
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\[[^\]]*\] # a single complete bracketed expression)
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)* # repeated as many times as possible
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''', re.X
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)
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return [x for x in term.findall(pattern) if x]
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def get_hosts(self, pattern="all"):
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"""
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find all host names matching a pattern string, taking into account any inventory restrictions or
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@ -164,7 +181,7 @@ class Inventory(object):
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# process patterns
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if isinstance(pattern, list):
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pattern = ';'.join(pattern)
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patterns = pattern.replace(";",":").split(":")
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patterns = self._split_pattern(pattern.replace(";",":"))
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hosts = self._get_hosts(patterns)
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# exclude hosts not in a subset, if defined
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@ -504,10 +521,10 @@ class Inventory(object):
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self._subset = None
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else:
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subset_pattern = subset_pattern.replace(',',':')
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subset_pattern = subset_pattern.replace(";",":").split(":")
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subset_patterns = self._split_pattern(subset_pattern.replace(";",":"))
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results = []
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# allow Unix style @filename data
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for x in subset_pattern:
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for x in subset_patterns:
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if x.startswith("@"):
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fd = open(x[1:])
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results.extend(fd.read().split("\n"))
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