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Generalise determination of hacking directory path

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Bash needs a special case to determine the dirname of the sourced path
(the hacking dir), but in all other cases, using $0 allows the script to
be sourced also from within the hacking directory, not only from its
parent.

Signed-off-by: martin f. krafft <madduck@madduck.net>
This commit is contained in:
martin f. krafft 2013-06-14 10:31:01 +02:00
parent 39aa5e5eac
commit 581dea70d1
1 changed files with 6 additions and 5 deletions
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11
hacking/env-setup
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@ -3,11 +3,12 @@
# modifies environment for running Ansible from checkout
# When run using source as directed, $0 gets set to bash, so we must use $BASH_SOURCE
if [ -n "$BASH_SOURCE" ] ; then
HACKING_DIR=`dirname $BASH_SOURCE`
else
HACKING_DIR="$PWD/hacking"
fi
case "$0" in
(bash)
HACKING_DIR=${BASH_SOURCE%/*};;
(*)
HACKING_DIR=${0%/*};;
esac
# The below is an alternative to readlink -fn which doesn't exist on OS X
# Source: http://stackoverflow.com/a/1678636
FULL_PATH=`python -c "import os; print(os.path.realpath('$HACKING_DIR'))"`